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Solution Manual for Engineering Circuit Analysis 9th Edition Hayt / All Chapters 1 - 18 / Full Complete 2023-2024

Solution Manual for Engineering Circuit Analysis 9th
Edition Hayt / All Chapters 1 - 18 / Full Complete
2023-2024
For the function f(x) = (ax^3-6x), if x ≤ 1, & f(x) = (bx^2+4),
x > 1 to be continuous and differentiable, a = ..... - ANS-for
the function to be continuous f(1) has to equal f(1):
a(1^3) -6(1) = b(1^2) +4
a -6 = b +4
b=a-10
for the functions to be differentiable f'(1) has to equal f'(1):
3a(1^2) -6 = 2b(1)
3a -6 = 2b
plug b from the first equation in to find a:
3a -6 = 2(a -10)
a = -14
Find k if f(x) = (k) at x = 4 and f(x) = ((x^2 -16)/(x-4)) -
ANS-1. f(4) exists and is equal to 8
2. lim from the left and right are both 8
3. lim f(x) as x approaches 4 is 8 which equals f(4)
k must equal 8
If f(x) is continuous and differentiable and f(x) = (ax^4 +5x)
for x ≤ 2, & f(x)= (bx^2 -3) for x > 2 , then b =... - ANS-Plug
x = 2 into both pieces.
f(x) = (16a +10) for x ≤ 2, & (4b -6) for x > 2
They must be equal to be continuous
16a +10 = 4b -6
a=.25b-1
Find the midpoint Riemann Sum of cos(x^2) with n = 4,
from [0, 2] - ANS-Mid S4 = (1)(1/2)[cos(.25^2) +
cos(.75^2) + cos(1.25^2) + cos(1.75^2)]
Mid S4 = (1)(1/2)[cos(.625) + cos(.5625) + cos(1.5625)
cos(3.0625)]
Mid S4 = .824
If the function f is continuous for all real numbers and if f(x)
= (x^2-7x +12)/(x -4) when x ≠ 4 then f(4) = - ANS-Factor
numerator so
f(x) = (x-3)(x-4)/(x-4) = x-3
f(4)=4-3
f(4) = 1
If f(x) = (x^2+5) if x < 2, & f(x) = (7x -5) if x ≥ 2 for all real
numbers x, which of the following must be true?
I. f(x) is continuous everywhere.
II. f(x) is differentiable everywhere.
III. f(x) has a local minimum at x = 2. - ANS-At f(2) both the
upper and lower piece of the discontinuity is 9 so the
function is continuous everywhere.
At f'(2) the upper piece is 4 and lower piece is 7 so f(x) is
not differentiable everywhere.
Since the slopes of the function on the left and right are
both positive the function cannot have a local minimum or
maximum at x= 2.
Only I is true

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Specificaties

Niveau: University
School: Chamberlain
Opleiding: Nursing
Studiejaar: 2024
Document
Rubriek: Tentamens
Gemaakt op: 01-08-2024
Type: .pdf
Pagina's: 13
Taal: English

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